Example 1 A soil sample has a void ratio of 0.8, degree of saturation of 0.9 and Gs of 2.68. Using SI units compute, total unit weight, dry unit weight, water content, and saturated unit weight. Solution Assume Vs = 1 m 3, Vv = 0.8 m 3, Vw = 0.9x0.8 = 0.72 m 3 Ww = 0.72 × 9.81 = 7.063 kN
he = specific evaporation enthalpy of steam (kJ/kg, Btu/lb) The heat transfer rate - or power - in a condensing steam flow can be expressed as. q = he ms (2) where. q = heat transfer (kW, Btu/h) ms = steam flow rate (kg/s, lb/h) Properties of Saturated Steam - Imperial Units. Properties of Saturated Steam
Metal Forming and Stamping Presses Improve productivity and safety in forming and stamping applications This paper takes a closer look at the automation and information solutions available for metal forming and stamping press systems.
Chapter 2: The Basics of Supply and Demand 8 To find the free market price for apartments, set supply equal to demand: 100 - 5P = 50 + 5P, or P = $500, since price is measured in hundreds of dollars. Substituting the equilibrium price into either the demand or
Cooling Tower Tons A cooling tower ton is defined as: 1 cooling tower ton = 1 TONS evap = 1 TONS cond x 1.25 = 15000 Btu/h = 3782 k Calories/h = 15826 kJ/h = 4.396 kW The equivalent ton on the cooling tower side actually rejects about 15000 Btu/h due to the heat-equivalent of the energy needed to drive the chiller's compressor.
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I need to know the power of a motor in Hp required to move a vehicle of about 150 Kg. The vehicle is equipped with gear assembly and required to run at 20 to 25 Km/h. This has to be converted to
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A comprehensive look at the US steel flat-rolled market US Steel flat-rolled products for the week of July 30, 2021 Fastmarkets’ daily steel hot-rolled coil index, fob mill US was calculated at $63 per hundredweight ($1,260 per short ton) on Thursday March 4, up by 1.04% from $62.35 per cwt on Wednesday and by 1.86% from $61.85 per cwt on February 25.
AREN 2110 SOLUTIONS FALL 2006 HOMEWORK ASSIGNMENTS 6, 7 and 8 & 5-61 Air is accelerated in a nozzle from 30 m/s to 180 m/s.The mass flow rate, the exit temperature, and the exit area of the nozzle are to be determined. Assumptions 1 This is a steady-flow process since there is no change with time.
CEE 345 Spring 2002 Problem set #2 Solutions Solution: n = 1500 rpm 60 s=min =25 rps ns = n p Q (gh)34 25 s1 p 12 cfs (32:2 ft=s2 25 ft)34 =0:57 Then from Fig. 8-15, ns <0:60 so use mixed o w pump. Problem 8.23 You want to pump water at a rate of 1:0 m3=s from the lower to the upper reservoir
16/11/2017 · Water-cooled chillers range in size from small 20-ton capacity models to several thousand-ton models that cool the world’sPerfectst facilities such as airports, shopping malls and other facilities. A typical water-cooled chiller uses recirculating condenser water from
29/4/2020 · 16 tons low voltage rail powered Coil Transfer trolley April 2, 2020 Brand Name: Ruixing Certification: CE,ISO9001 Model : KP-16-1 Minimum Order Quantity: 1 set/sets Packaging Details: Suitable for sea transport or […]